ACETYLENE CAN BE PREPARED FROM CALCIUM CARBONATE BY A SERIES OF REACTIONS.THE MASS OF 80% CALCIUM CARBONATE REQUIRED TO PREPARE 2MOLES OF ACETYLENE IS?

Dear Student,

The reactions for preparation of acetylene from calcium carbonate are:

$$\begin{gathered} CaC{O}_3+3C \to Ca{C}_2 + 3CO \\ Ca{C}_2 +2H_{2}O \to C_2{H}_2 + Ca(OH{)}_2 \\ So, molar ratio of CaC{O}_3 :C_2{H}_2 = 1:1 \\ So, 2 moles of CaC{O}_3 are required to make 2 moes of acetylene \\ So weight of CaC{O}_3 required = 2 x molar mass = 2 x 100 = 200 g \\ Now, let the total mass of the solution be z. \\ So, 80\% by mass of z is 200 g. \\ So, z = \frac{200\times 100}{80}=250 g \end{gathered}$$
So, 250 g of 80% by mass of calcium carbonate is required.

Hope it helps.

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