after covering a distance of 30 km with a uniform speed there is some defect in a train engine and therefore; its speed is reduced to 45 of its orignal speed.consequently, the train reaches is destination late by 45 minutes.Had it happened after covering 18 kilometers more, the train would have reached 9 minutes earlier.Find the speed of the train and the distance of the journey. HURRRRY HURRRY GIVE THE ANSWER
Let the original speed of the train be x km/hr and the length of the journey be y km.
When x = 30, we get
3 × 30 – y = –30
⇒ –y = –30 – 90 = –120
⇒ y = 120
∴ Original speed of the train = 30 km/hr
Length of the journey = 120 km