after repolarisation the neuron attains resting stage then the potassium and sodium is replaced by pumpimg 3na out and 2k in so is na/k+ pump is a leak channel which is always open??

Dear student
At a site (B) that is adjacent to the depolarised site (A), the outer surface of the membrane has positive charge and the
​​​​​inner surface has negative charge.

Depolarised site (A): Positive (in) and Negative (out) 
Adjacent site (B): Positive (out) and Negative (in)

Current flow on the inner surface: Site A to B 
Current flow on the outer surface: Site B to A

This completes the circuit of current flow. Polarity of site B is reversed and action potential is generated at site B.

Hence, the impulse travels to site B, and we say that this impulse is conducted. This sequence is repeated along the length of the axon.

Stimulus-induced permeability to Na  is short-lived, and is quickly followed by permeability to K . When this happens, the resting potential is restored, and once more, the site can be stimulated.  

At a site (B) that is adjacent to the depolarised site (A), the outer surface of the membrane has positive charge and the inner surface has negative charge.

Depolarised site (A): Positive (in) and Negative (out) 
Adjacent site (B): Positive (out) and Negative (in)

Current flow on the inner surface: Site A to B 
Current flow on the outer surface: Site B to A

This completes the circuit of current flow. Polarity of site B is reversed and action potential is generated at site B.

Hence, the impulse travels to site B, and we say that this impulse is conducted. This sequence is repeated along the length of the axon.

Stimulus-induced permeability to Na  is short-lived, and is quickly followed by permeability to K . When this happens, the resting potential is restored, and once more, the site can be stimulated.  

​​​​​​​Regard

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