Age No.of girls

18 - 23

x 23- 28 170 28- 33 y 33- 38 50 38- 43 38

43-48

48-53

10

2

the frequency distribution table shows the ages of 560 girls at the time of their marriage in a city. If mode of the age of the data is 24 years, find missing frequency.

class intervals Frequency
18-23 x
23-28 170
28-33 y
33-38 50
38-43 38
43-48 10
48-53 2


ifi = 560270+x+y = 560x + y = 290   ....1Now, mode = 24So, modal class = 23-28Frequency of modal class = f1 = 170frequency of class preceeding modal class = f0 = xfrequency of classsucceeding modal class = f2 = ylower limit of modal class, l = 23class size, h = 5Now, mode = l + f1-f02f1-f0-f2×h24 = 23 + 170-x340-x-y×55170-x = 340-x-y850-5x = 340-x-y510 = 4x-y4x-y = 510    ......2Adding 1 and 2, we get5x = 800x = 160Now, from 1, y = 130

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