Balance the following Al(OH)3 ---> Al2O3 + H2O
The rule for balancing equations is "the number of atoms of each element on the reactant side must be equal to the number of atoms of each element on the product side" .
TIPS before balancing quations:
1.Start with the highest occuring frequency element.
2.If you get two elements of same fequency, start with a metal.
Balancing :
The euqation we need to balance is Al(OH)3 ----->Al2O3 + H2O
Step1:Write the frequencies of all the elements in the reaction
L.H.S:Al = 1 O = 3 H = 3
R.H.S:Al = 2 O = 4
Step2:Start off with Oxygen(Highest occuring frequency)
Let me try by writing 2 as the coefficient of Al(OH)3
Step3:Get Oxygen atoms equal on R.H.S with L.H.S
Now at L.H.S there are 6 Oxygen Atoms ,what should I do at the R.H.S??I write 3H2O.
Oxygen looks equal on both the sides.
Step4:Check the frequency
We obtain a new equation 2Al(OH)3 ----> Al2O3 + 3H2O
L.H.S:
Al = 2
O = 2 * 3 = 6
H = 2 * 3 = 6
R.H.S:
Al = 2
O = 3 + 3 = 6
H = 2 * 3 = 6
Well, you have balanced the equation.
The balanced quation is 2Al(OH)3 ----> Al2O3 + 3H2O
