Aluminium wire of resistance R is pulled so that its length becomes 4 times its orginal length. Find the new resistance of the wire in terms of its original resistance.
pls guys... give me the answer.....!!!!!
Suppose original length of wire=L,cross sectional area=A
Then resistance,
Now length of wire L in increased 4 times by pulling i.e L'=4L .It means its cross sectional area will become A/4 i.e A'=A/4
Then new resistance will be