Among the isomeric alkanes of molecular formula C₅H₁₂ identify the one that on photochemical chlorination yields (i) a single monochloride. (ii) three isomeric monochlorides. (iii) four isomeric monochlorides. Kindly explain how the answers are arrived,i mean the basic principles to be bear in mind while solving such questions.Kindly help

(i) To have a single monochloride, there should be only one type of H-atom in the isomer of the alkane of the molecular formula C₅H₁₂. This is because, replacement of any H-atom leads to the formation of the same product. The isomer is neopentane.

Neopentane

(ii) To have three isomeric monochlorides, the isomer of the alkane of the molecular formula C₅H₁₂ should contain three different types of H-atoms.

Therefore, the isomer is n-pentane. It can be observed that there are three types of H atoms labelled as a, b and c in n-pentane.

(iii) To have four isomeric monochlorides, the isomer of the alkane of the molecular formula C₅H₁₂ should contain four different types of H-atoms. Therefore, the isomer is 2-methylbutane. It can be observed that there are four types of H-atoms labelled as a, b, c, and d in 2-methylbutane.