Among two supplementary angles the measure of the larger angle is 44 degrees more than the measure of the smaller. Find their measures.

let the smaller angle wil be x

its larger angle will be 44^{o}+ x

A/q the equation will be 44^{o}+ x + x =180^{o}

^{=> }44^{o} + x+ x = 180^{o}

^{=> }44^{o} + 2x = 180^{o}

=> 2x = 180^{o }+ 44^{o}

=> 2x = 136^{o}

=> x = 136^{o}/2

=> x =68^{o}

so, the measure of smaller angle is 68^{o}

the measure of larger angle is 44^{o} + 68^{o} = 112^{o}

^{ }