Among two supplementary angles the measure of the larger angle is 44 degrees more than the measure of the smaller. Find their measures.
let the smaller angle wil be x
its larger angle will be 44o+ x
A/q the equation will be 44o+ x + x =180o
=> 44o + x+ x = 180o
=> 44o + 2x = 180o
=> 2x = 180o + 44o
=> 2x = 136o
=> x = 136o/2
=> x =68o
so, the measure of smaller angle is 68o
the measure of larger angle is 44o + 68o = 112o