amount of KMnO4 required to prepare 100ml of 0.1 N solution in alkaline medium Share with your friends Share 1 Shruti Srivastava answered this Dear Ina Vashishtha, In alkaline medium the change in oxidation no. of Mn is from+7 to +6 so n-factor is 1.so equivalent wt of permanganate is 158 only or equal to m.wt.eq. wt=m.wtn-factorso wtof permanganate can be calculated0.1=wt158×1000100wt=1.58 g of KMnO4Regards 9 View Full Answer
