an A.P. consists of 60 terms.if the first and the last terms be 7 and 125 respectively,find 32nd term.
a=7
an=125
n=60
hence,an=a+[n-1]d
125=7+[60-1]d
125-7=59d
118/59=d
2=d
therefore,32nd term=a+31d
=7+31[2]
=7+62
=69
an A.P. consists of 60 terms.if the first and the last terms be 7 and 125 respectively,find 32nd term.
a=7
an=125
n=60
hence,an=a+[n-1]d
125=7+[60-1]d
125-7=59d
118/59=d
2=d
therefore,32nd term=a+31d
=7+31[2]
=7+62
=69