An ac circuit consists of a series combination of circuit elements X and Y. The current is ahead of the voltage by phase pi/4. If the element X is a pure resistor of 100 Ohm, (i) identify the circuit element Y and (ii) calculate the rms current if rms voltage is 141 V.
Hello Ankit Vijay dear, as current is ahead then the circuit is capacitive. Hence element Y has to be a capacitor
Impedance Z = √R^2 + Xc^2
R = 100 Ω
Xc / R = tan pi/4
==> Xc = R = 100 Ω
Z = 100 √2 Ω
Therefore I rms = Erms / Z = (141 / 100√2) A = 0.9987 A = 1 A nearly
Impedance Z = √R^2 + Xc^2
R = 100 Ω
Xc / R = tan pi/4
==> Xc = R = 100 Ω
Z = 100 √2 Ω
Therefore I rms = Erms / Z = (141 / 100√2) A = 0.9987 A = 1 A nearly