An aeroplane touches down at 225km/hr and stops after 2min. Calculate (i)acceleration (ii)length of the runway

Dear Student ,
After touching down the aeroplane's velocity was 225 km/hr and it stops after 2 min .
Let us take that the aeroplane stops after going through s distance and a be the accelration of it .
Now as the aeroplane stops after s distance so , final velocity is zero and initial velocity is 225 km/hr .
$$\begin{gathered} \left(i\right)Now from the equation of motion we can write that , \\ v=u+at \\ \Rightarrow 0=\left(225\times \frac{5}{18}\right)+120a \left[t=2 min=120 sec\right] \\ \Rightarrow 120a=-62·5 \\ \Rightarrow a=-0·52 m/s^2 \\ Now here the negative sign indicates the acceleration is negative ,i.e it is retardation . \\ \left(ii\right)Again from the equation of motion we can write that , \\ {v}^2=u^2+2as \\ \Rightarrow 0={\left(62·5\right)}^2+2\times \left(-0·52\right)\times s \\ \Rightarrow s=\frac{{\left(62·5\right)}^2}{2\times 0·52}=3750 m \end{gathered}$$
Regards