An aeroplane when flying at a height of 400 m from the ground passes vertically above another aeroplane at an instant when the angle of elevation of 2 planes from the same point on the ground are 60degree and 45 degree. Find the vertical distance btw the aeroplane at that instant

Let A and B be the positions of two Aeroplanes, when B is vertically below A  In ΔCDB,tan45°=BCCD1=BCCDCD=BCCD=400 m   as BC=400 mIn ADCtan60°=ACCD3=AB+BCCD3=AB+4004004003=AB+400AB=4003-400 mAB=4003-1m

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