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An arrangement of three blocks is shown in figure. The string and pulley are ideal. There is no friction between 6 kg block and ground. There is friction between 5 kg and 6 kg block (µ = 0.8). The maximum value of mass m, such that the two blocks (5 kg and 6 kg) will move together, is


(1) 44 kg               (2) 22 kg                  (3) 40 kg                   (4) 4 kg

the options seem to be incorrect. plz recheck ur question and options. a
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22 kg
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An arrangement of 3 blocks is shown into figure

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Make FBDs for all the blocks. The eqns will come out as T -40 = 5a......... (i) from FBD of first block.(f =40N) f = ma from FBD of 2nd block. 40 = 6a. a = 40/6 m/s^2 Putting this in eqn 1, we get T as 220/3N. From FBD of block of mass m, mg - T = ma. Upon solving, m comes out as 22kg..
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