an artificial satellite is orbiting at 500 km above the earth's surface. take the radius of earth as 6.5 * 106 .
  1. ​​​​find the acceleration due to gravity at any point along the satellite path.
  2. What is the centripetal acceleration of the satellite?

g` be the acceleration due to gravity at any point in the path.

g`=g(1+h)-2
  =9.8(1+5006.5*106)-2
   
centripetal acc =GMm
2
 
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its not the answer
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answer is 8.45
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what is the right answer ?
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is Suman's answer correct ?
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See the solution below

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Hi DEVANSH I am ADITYA VIKRAM
  • -12
answer is 8.45 . @avinash singh answer is correct


 
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centripetel acceleration=v2/r
v is orbital velocity i.e=root gm/r
substitute the value of v i in v2/r and we get( root gm/r)2/r=GM/r2=g=8.45ms-2
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