An egg vendor calls on his first customer and sells half his eggs and half an egg. To the second customer, he sells half of what he has left with and half an egg, and to the third customer , he sells half of what he was then left with and half an egg. however, he did not break any egg. If in the end, the vendor was left with three eggs the what number of eggs did he have initially?
a)26  (b)31  (c)39  (d) none of these

Dear Student,
Please find below the solution to the asked query:

The trick lies in the statement that he does not break any egg.Let number of eggs be x.He sells x2+12 eggs to first customer.Hence he is left withx-x2+12=x-x2-12=x2-12=x-12Similarly after dealing with second customer, he is left with x-1-22×2=x-34Similarly after dealing with third customer, he is left with x-3-42×4=x-78According to questionx-78=3x-7=24x=24+7=31 Answer

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  • -1
The correct ans. is 31. U let the total no. of eggs as x . then after selling eggs to 1st, he is left with x-1 / 2 eggs. after selling to 2nd , he is left with x-3/4 eggs. Then, after selling to 3rd, he is left with x-7/8 eggs . A/Q. x-7/8 = 3.
This gives x- 7 =24 Therefore, x=31
Hence, no. of eggs initially = 31
  • 2
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