An electric bulb suspended from the roof of a railway train by a flexible wire shifts through an angle of 19°48' when the train goes horizontally round a curved path of 200 m radius find the speed of the train

Dear student,

When the train takes the turn there is some tension in the string such that
T x cos θ = mg
T x sin θ = mv²/r

Dividing these two

tan θ = v²/rg
v = √(rg tan θ​​​​​​​)

r = 200
θ = 19⁰48' = 19.8^o

Thus v = √720 = 26.8 m/s

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​Hope this information will clear your doubts about topic. Regards