an electric dipole of dipole moment 20 *10-6Cm is enclosed by a closed surface .what is the net flux coming out of the surface?
The net flux through a surface can be found by considering a closed Gaussian surface enclosing the charges. The flux is equal to the net charge divided by ε0.
In the question, the enclosed by a Gaussian surface due to the dipole is = +q + (-q) = 0
Therefore, the flux is, ϕ = 0/ε0 = 0