an electric dipole of dipole moment 20 *10-6Cm is enclosed by a closed surface .what is the net flux coming out of the surface?

The net flux through a surface can be found by considering a closed Gaussian surface enclosing the charges. The flux is equal to the net charge divided by ε0.

In the question, the enclosed by a Gaussian surface due to the dipole is = +q + (-q) = 0

Therefore, the flux is, ϕ = 0/ε0 = 0 

  • 89

zero because net charge inside the closed surface is zero.

  • 12

thanx..

  • -8

it will be zero..

  • -7
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