An electric dipole of length 1 cm which placed with its Axis making an angle of 60 degree with uniform electric field experiences the torque of 6 root 3 Newton metre calculate the potential energy of the dipole if it has a charge of 2 Nano coulomb

Dear Student,
                    As we know the torque on a dipole placed in uniform electric field is given by,
                                                                     ζ =  p X E = pE sinθ​ = pEsin60​o3 /2 pE                 [given in the ques, angle = 60o]
                                      the value of tourque is given in ques,  
ζ 63  Nm 
                                   so we get,    pE = 12                ................(1)


                              Now we know potential energy of dipole, U = - p . E =- pE cosθ​ = -pE cos60o= - pE  / 2            ..................(2)
                                           Putting the value of 'pE' from eqn (1)  to eqn (2) we get,
                                                                                                          U = - 12 / 2
                                                                                                          U = - 6 J

        Regards.

 

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