An electric flux of -5 X 10-3 Nm2/C passes through a spherical Gaussian surface of radius 20 cm due to - Physics - Electrostatic Potential And Capacitance

Question

An electric flux of -5 X 10-3 Nm2/C passes
through a spherical Gaussian surface of radius 20 cm due to a
charge placed at its centre
Calculate the charge enclosed by the Gaussian surface
If the radius of the gaussian surface is doubled how much flux will
pass through the surface?

Ravi Gupta · Accepted Answer

flux = charge enclosed/ε0 charge enclosed = flux×ε0 = -5×10-3×8
85×10-12 =44 2×10-15 C 
Flux is independent of the radius of the gaussian surface

An electric flux of -5 X 10-3 Nm2/C passes through a spherical Gaussian surface of radius 20 cm due to a charge placed at its centre. Calculate the charge enclosed by the Gaussian surface. If the radius of the gaussian surface is doubled how much flux will pass through the surface?

An electric flux of -5 X 10^-3 Nm²/C passes through a spherical Gaussian surface of radius 20 cm due to a charge placed at its centre.
Calculate the charge enclosed by the Gaussian surface.
If the radius of the gaussian surface is doubled how much flux will pass through the surface?