AN ELECTRIC POLE CASTS A SHADOW OF LENGTH 20 METRES AT A TIME WHEN A TREE 6 METRES HIGH CASTS A SHADOW OF LENGTH 8 METRES. FIND THE HEIGHT OF THE POLE.

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Please find below the solution to the asked query:

Given : A electric pole cast a shadow = 20 m and at a time a tree of 6 m high cast a shadow of 8 m

Let height of electric pole =  x Then ,

$$\begin{gathered} \frac{x}{20} = \frac{6}{8} \\ \Rightarrow \frac{{\displaystyle x}}{{\displaystyle 20}} = \frac{{\displaystyle 3}}{{\displaystyle 4}} \\ \Rightarrow x = \frac{{\displaystyle 3}}{{\displaystyle 4}} \times 20 \\ \Rightarrow x = 3 \times 5 \\ \mathbf{\Rightarrow }\mathit{x}\mathbf{ }\mathbf{=}\mathbf{15}\mathbf{ } \end{gathered}$$
Therefore,

Height of electric pole = 15 m                                                           ( Ans )


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