An electromagnetic wave of electric field E=10 sin(wt - kx) N/C is incident normal to the cross sectional area of cylinder 10 cm/m×m and having length 100 cm, lying along x-axis. Find energy density, energy contained in the cylinder, the intensity of the wave, momentum transferred to the cross sectional area of cylinder in 1 s considering total absorption and the radian pressure.


Dear Student,
                     we know energy density of the EM wave =12ε0E02=12×8.85×10-12×100=4.425×10-10Jm-3as here  E0=10V/mand energy contained in cylinder(U)=energy density×volume of the cylinder=4.425×10-10×10×10-4×1=4.425×10-13and intensityI=energy density×speed of wave=4.425×10-10×3×108=0.13275W/m2momentum transfered per second =energy density×cross section=4.425×10-10×10×10-4=4.425×10-13Nsand radiation   pressure=Ic=4.425×10-10pa
Regard

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