An electron & a photon each having a wavelength of 1nm . Calculate-
(i) Momentum
(ii) Energy
(iii) Kinetic Energy of Electron

Solution
According to De Broglie hypothesisp=hλ =6.62×10-341×10-9 = 6.62×10-25 kg .m/sThe value remains same irrespective of electron or photon.Energy of photon and electronE = pc =6.62×10-25 ×3×108 =19.86×10-17 JKinetic energy of electronK.E. =p22m =6.62×10-25 ×6.62×10-25 2×9.1×10-31 =2.41×10-19   J

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