An electron & a photon each having a wavelength of 1nm . Calculate- (i) Momentum (ii) Energy (iii) Kinetic Energy of Electron Share with your friends Share 0 Vipra Mishra answered this Solution According to De Broglie hypothesisp=hλ =6.62×10-341×10-9 = 6.62×10-25 kg .m/sThe value remains same irrespective of electron or photon.Energy of photon and electronE = pc =6.62×10-25 ×3×108 =19.86×10-17 JKinetic energy of electronK.E. =p22m =6.62×10-25 ×6.62×10-25 2×9.1×10-31 =2.41×10-19 J 0 View Full Answer