An electron beam can undergo diffraction by crystal. through what potential should be a beam of electrons be accelerated so that its wavelength becomes eaual to 1.54Angstom.Please explain the answer also.

Mass of electron = 9.1 × 10-31 kg

calculating momentum of electron using...

Kinetic energy of electron = p2/2me

=(4.25 x 10-24)2/ (2 x 9.1 × 10-31 )

=1 x 10-17  J

 

Now

K.E. of electron = eV

or

V = K.E/e

=1 x 10-17  J /1.60217646 × 10-19

=62.5 V

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