An electron beam can undergo diffraction by crystal. through what potential should be a beam of electrons be accelerated so that its wavelength becomes eaual to 1.54Angstom.Please explain the answer also.
Mass of electron = 9.1 × 10-31 kg
calculating momentum of electron using...
Kinetic energy of electron = p2/2me
=(4.25 x 10-24)2/ (2 x 9.1 × 10-31 )
=1 x 10-17 J
Now
K.E. of electron = eV
or
V = K.E/e
=1 x 10-17 J /1.60217646 × 10-19
=62.5 V