An electron is moving with a velocity of 2 5 x 106 m/s lf the uncertainty in its velocity - Chemistry - Structure of Atom

Question

An electron is moving with a velocity of 2 5 x 106 m/s lf the
uncertainty in its velocity is 0 1% Calculate the
uncertainty in its position (Planck’s constant, h = 6 626 x
10-34 Js Mass of the electron = 9 1 x 10-31 kg)

Yasodharan · Accepted Answer

Dear Student,

The computation is expressed below using Heisenberg's uncertainity
principle,

v=2 5×106 msh=6 623×10-34 Js me=9
1×10-31 kg∆v=2 5×106×0
1100=2500 msuncetainity position is,∆x=hnπ×1me∆v=6
626×10-344π×19 1×10-31×2500=2
3×10-8 mthe above calculation is for n=4 and by varying "n" value the uncertainity position varies

Regards

An electron is moving with a velocity of 2.5 x 106 m/s. lf the uncertainty in its velocity is 0.1%. Calculate the uncertainty in its position. (Planck’s constant, h = 6.626 x 10-34 Js. Mass of the electron = 9.1 x 10-31 kg).

An electron is moving with a velocity of 2.5 x 106 m/s. lf the uncertainty in its velocity is 0.1%. Calculate the
uncertainty in its position. (Planck’s constant, h = 6.626 x 10-34 Js. Mass of the electron = 9.1 x 10-31 kg).