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An element E of atomic mass 150g/mol crystallises into an FCC lattice of edge length 600pm the no. of atom present in 15g of element is ax10^{22 }. what is the value of a ?

The number of atoms can be simply found by finding out the number of moles and then multiplying it by Avogadro's number. We have been given the weight of the compound and the atomic mass.

So,

$Numberofmoles=\frac{Givenmass}{molarmass}=\frac{15}{150}=0.1mol\phantom{\rule{0ex}{0ex}}Numberofatoms=Numberofmoles\times {N}_{A}=0.1\times 6.022\times {10}^{23}=6.022\times {10}^{22}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$

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Thus, the value of a is 6.022.

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