An elevator descends into a mine shaft at the rate of 8m/min. If it starts descending from 5m above the ground level, how long will it take to reach -195m?
Dear student,
speed of descent of the elevator =
initial position of the elevator: 5 m above the ground level
final position of the elevator = 195 m below the ground level
time taken to reach there =
Hence, it will take 25 minute to reach -195 m form +5 m.
Regards
speed of descent of the elevator =
initial position of the elevator: 5 m above the ground level
final position of the elevator = 195 m below the ground level
time taken to reach there =
Hence, it will take 25 minute to reach -195 m form +5 m.
Regards