An elevator descends into a mine shaft at the rate of 8m/min. If it starts descending from 5m above the ground level, how long will it take to reach -195m?

Dear student,

speed of descent of the elevator = 8 m/min
initial position of the elevator: 5 m above the ground level
final position of the elevator = 195 m below the ground level
time taken to reach there = total distancespeed                     ( speed =distancetime  )
                                           =5+1958= 25 min

Hence, it will take 25 minute to reach -195 m form +5 m.


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