an elevator weighing 500 kg is to be lifted up at a constant velocity of 0.4m/s . what should be the minimum horse power of the motor to be used?

Given
Force = m g = 500 kg x 9.8 m/s²=4900 N
Velocity = 0.4 m/s
Now, power=Force x velocity
=4900 x 0.4=1960 W
Now 1 W = 0.00134 hp
So, 1960 W=1960 x 0.00134=2.6 hp