an ice berg of density 900kg/m3 is floating in water of density 1000 kg/m3. the percentage of volume of ice cube outside the water is:- 20% 35% 10% 25% Share with your friends Share 13 Geetha answered this densityice = VoutVtot × densitywater 900 =VoutVtot × 1000Vout = 9001000 × Vtot = 110 × VtotSo the fraction of ice coming out =110% of volume of ice = 110 × 100 = 10 % -17 View Full Answer