an ice berg of density 900kg/m3 is floating in water of density 1000 kg/m3. the percentage of volume of ice cube outside the water is:-
  • 20%
  • 35%
  • 10%
  • 25%

densityice = VoutVtot × densitywater 900 =VoutVtot × 1000Vout  = 9001000 × Vtot          = 110 × VtotSo the fraction of ice coming out =110% of volume of ice = 110 × 100 = 10 %

  • -17
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