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an ion M a has the magnetic moment equal to rt 24 BM.the value of a is

Magnetic moment = √24 (given )

√ 24 = √{n(n+2)}

24 = n (n+2)

n = 4

Therefore M has 4 unpaired electrons .

To gain octect configration it either has to gain or loose 4 electron or share electron ,

Simce it is an ion ; a = 4
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anser is 2 but how??
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Since Magnetic moment = n(n+2)−−−−−−−√n(n+2) = 4.9
∴∴ n= 4(where n is no. of unpaired electron)
Thus Mna+Mna+ ion has four unpaired electron 25Mn3+:1S2,2S2 2P6,3S2,3P6 3d4 
 25Mn3+:1S2,2S2 2P6,3S2,3P63d4
∴∴ a = 3
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We know root 24=4.89 approximately Which means that no of unpaired electrons are 4 Now we have to find a Configuration of element with atomic no 24 will be 3d^4 4s^2 so there are 2 electrons which goes missing for making the no of unpaired electron so 4 so a=2 Hope you understand

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