An iron rod of 0.5 cm2 area of cross section is subjected to a magnetizing field of 1200 Am-1. If magnetic susceptibility of iron is 599, calculate (i) µ (ii) B (iii) φ (magnetic flux) produced.

Dear Student,

μ=μ01+χμ=4π×10-7×1+599μ=7.536×10-4 T m/AB=μHB=7.536×10-4×1200B=0.904 TMagnetic flux, ϕ=BAϕ=0.904×0.5×10-4ϕ=1.808×10-4 Wb

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