An iron sample contains 18% Fe3O4 . What is the amount that is precipitated as Fe2O3 which weighs 0.40g.
Dear Student,
The balanced reaction scheme is expressed below,
It is clear 2 mole of Fe3O4 precipitates to 3 mole of Fe2O3 the ratio is 1:1.5 by using this the % will be (18x1.5=27%) so the precipitated amount is 0.4 gm x 27% =0.108 gm
Regards.
The balanced reaction scheme is expressed below,
It is clear 2 mole of Fe3O4 precipitates to 3 mole of Fe2O3 the ratio is 1:1.5 by using this the % will be (18x1.5=27%) so the precipitated amount is 0.4 gm x 27% =0.108 gm
Regards.