An L shaped glass tube iS kept Inside a bus  that is  moving with constant acceleration. During the motion, the level of the liquid in the left arm is at 12 cm where as in the right arm, it is 8 cm when th orientation of the tube is as shown. Assuming that the diameter Of the tube is much smaller than levels of the liquid and neglecting effect of surface tension, acceleration of the bus find the (g=10 m/s sq.)




In fluid mechanics how is it so?
 

I don't know
  • -4
2 m/s.s
  • -3
Given: Height of left arm liquid, h1=12cm and right arm, h2=8cm
From the above diagram, θ=45o,tan⁡θ=ag
⟹ag=h1−h2h1tan⁡45∘+h2tan⁡45∘
⟹ag=h1−h2h1+h2
⟹ag=12−812+8
⟹ag=420
⟹a=10×420=2ms−2
So, we get acceleration of bus will be 2ms−2.
  • -1
What are you looking for?