An object 6 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.
PLEASE ANSWER FAST!!!!!!

Dear Student

Radius of curvature (R) = 30 cm

f = R/2 = 30/2 = 15 cm

u = -20 cm,

h= 6 cm.
1v +1u=1f1v =1f-1u1v =115-1(-20)  v = 8. 57 cm  Image is virtual and erect and formed behind the mirror.  m = -vu  m = IO  =-vuI6=-8.57(-20) = 0.428  I = 0.428 x 6 =2.468cm

Position of Image: Behind the mirror.

Nature of Image: Virtual and Erect.

Size of the Image: Diminished.



Regards

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