An object hangs from the spring balance. The balance indicates 30 N in air and 20 N when the object is submerged in water. What does the balance indicate when the object is submerged in a liquid with a density that is half that of water?
Dear Student,
Please find below the solution to the asked query:
upthrust offered by water = weight in air-weight in water = 30-20=10N
Now,
also,
U = V×dwater×g
10 = V × 1000×10
V = 10-3 m3
Now,
when the object is immersed in liquid whose density is half that of water,
then
U' = V × dliquid×g
U' = 10-3×500×10
U' = 5 n
Reading on the spring balance = weight in air- upthrust = 30-5 = 25N
Hope this information will clear your doubts about ( Force and pressure ).
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Satyendra Singh
Please find below the solution to the asked query:
upthrust offered by water = weight in air-weight in water = 30-20=10N
Now,
also,
U = V×dwater×g
10 = V × 1000×10
V = 10-3 m3
Now,
when the object is immersed in liquid whose density is half that of water,
then
U' = V × dliquid×g
U' = 10-3×500×10
U' = 5 n
Reading on the spring balance = weight in air- upthrust = 30-5 = 25N
Hope this information will clear your doubts about ( Force and pressure ).
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Satyendra Singh