An object is moving along a straight line with uniform acceleration. The following table gives the velocity of the object at various instants of time.

Time (in seconds )

0

1

2

3

4

5

6

Velocity

(In m/s )

2

4

6

8

10

12

14

(i) Find the velocity of the object at the of 2.5 sec.

(ii) Calculate the acceleration

(iii) Calculate the distance covered in the last 4 sec.

a=v-u/t

a=4-2/1=2m/s

now fot t=2.5 

a=v-u/t

2=v-2/2.5

5=v-2

v=7

  • 16
ii) a=v-u/t        v=14 u=2 and t=6
a=14-2/6
a=12/6
a=2 m/s/1/s or 2 m/s power 2.
  • 13
iii) area of triangle = 1/2 * (14-6) * 4
                                  8*2= 18 m
  • 1
a=v-u/t a=4-2/1=2m/s2 now fot t=2.5 a=v-u/t 2=v-2/2.5 5=v-2 v=7
  • 0
this is question

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