An object is placed 25 cm in front of a concave lens of focal Length 25cm.Find the location and nature of image and plz tell how they are finding nature as magnification is not given??

Dear Student

u = - 25 cm
f = - 25 cm
​v = ?
By lens formula
1/f = 1/v - 1/u
1/-25=1/v - 1/-25
1/-25 = 1/v + 1/25
1/v = -2/25
v = -25/2
v = - 12.5 cm

The negative sign shows that the image is erect and virtual.

Regards