An object is placed at a distance of 30cm from a convex mirror, the magnification is 1/2. Where should the object be placed to get a magnification of 1/3 ?
Dear Student ,
Given:
u=-60cm
m=1/2
m=-v/u
1/2=-v/-60
-v=-30cm
v=30cm
f=?
by mirror formula:
-1/60+1/30=1/f
on solving:
f=60cm
m=1/3
1/3=-v/u
v=(1/3)u
f=60cm
using mirror formula:
1/u+1/v=1/f
1/u-3/u=1/60
u=-120cm
Regards
Given:
u=-60cm
m=1/2
m=-v/u
1/2=-v/-60
-v=-30cm
v=30cm
f=?
by mirror formula:
-1/60+1/30=1/f
on solving:
f=60cm
m=1/3
1/3=-v/u
v=(1/3)u
f=60cm
using mirror formula:
1/u+1/v=1/f
1/u-3/u=1/60
u=-120cm
Regards