an object of height 7 cm is kept at a distance of 25 cm in front of a concave mirror. the focal length of the mirror is 15 cm. at what distance from the mirror should a screen be kept so as to get a clear image ? what will be the size and nature of the image ?

Hi Khushi Sinha, let us follow mirror formula 1/u + 1/v = 1/f 
Given u = 25 cm, f = 15 cm
Now v = uf /(u - f)
==> v = 25 * 15 / 10 = 37.5 cm.
Screen has to be placed at a distance 37.5 cm to get the sharp image
Magnification = v/u = 37.5/25 = 1.5
Hence size of image will be 1.5 * 7 = 10.5 cm 
Nature of image :
Real
Inverted
Enlarged
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