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An object starts from rest with constant acceleration 4 m/s2,then find the distance travelled by object in 5th half second.

Distance travelled in 2.5 s:s1=ut+12at2    =02.5+1242.52    =12.5 mDistance travelled in 2.0 s:s2=ut+12at2    =02.0+1242.02    =8 mDistance travelled in 5th half second, that is, 2.5th second:s=s1-s2  =12.5 - 8   =4.5 m

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             U    = 0                                                                                                      ..............( 1 )
             A    = 4 ms-2
             S     = UT + (1/2)AT2
>>        S     = (1/2) AT2                  [ from (1) ]                                                     ...............( 2 )
Now 5th half second means S2.5 - S2 i.e. distance covered in 2.5 seconds - distance covered in 2 seconds
so
             S2.5th  = S2.5 - S2 = (1/2) A { (2.5)2 -4 }
>>        S2.5th  = (1/2) * 4 * 2.25     = 4.5m
Hence: The object travelled adistance of 4.5 meter in 5th half second.
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