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An object travels 40m in 5 sec and then another 80m in 5 sec. What is the average speed of the object?

(a) 12 m/s
(b) 6 m/s
(c) 2 m/s
(d) 0 m/s

(A)12m/sec
Total distance =(80+40)m
=120 m
Total time taken =(5+5)secs
=10 secs
Average speed= total distance/total time
=(120/10)m/sec
=12 m/sec
  • -2
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(A)12m/sec
Total distance =(80+40)m
=120 m
Total time taken =(5+5)secs
=10 secs
Average speed= total distance/total time
=(120/10)m/sec
=12 m/sec
  • -2
(A)12m/sec
Total distance =(80+40)m
=120 m
Total time taken =(5+5)secs
=10 secs
Average speed= total distance/total time
=(120/10)m/sec
=12 m/sec
  • -2
(A)12m/sec
Total distance =(80+40)m
=120 m
Total time taken =(5+5)secs
=10 secs
Average speed= total distance/total time
=(120/10)m/sec
=12 m/sec
  • 0

(A)12m/sec
Total distance =(80+40)m
=120 m
Total time taken =(5+5)secs
=10 secs
Average speed= total distance/total time
=(120/10)m/sec
=12 m/sec
  • -2
It is option A)
Cause avg. =  total dist. / total time
                 =   40 + 80 / 5 + 5
                =  120 / 10
                 =  12m/s
  • -2
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  • -1
OPTION A -- 12 
BCOZ 
AVG SPEED = TOTAL DIST / TOTAL TIME
                          120/10
                         = 10m/s
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A OBJECT Travels 40m in 5 seconds and then another 80m in 5 seconds what is the average of speed
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Total distance = 40+80=120m Total time =5+5=10sec Average velocity =Total distance travel/Total time taken 120/10m/sec 12m/sec
  • -1
12/3
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12mim/sec
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12mim/sec
  • -3
An object travels 40m in 5 sec and then another 80m in 5 sec. What is the average speed of the object
  • -3
Total time /total distance 40+80/5+5 m/s =120/10 m/s =12m/s
  • 0
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