An organic compound was found to contain the following constituents : C 33% H 4.7% N 13.2% Cl 33.4%. Determine the empirical formula.

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Assume 100 g of the compound is present. This changes the percents to grams:C=33 gH=4.7 gN=13.2 gCl=33.4 gConvert masses to moles:C=33 12=2.75 molH=4.71=4.7 molN=13.214 =0.94 molCl=33.435.5 =0.94 molDivide tby the lowest, seeking the smallest whole number ratioC=2.750.94=3H=4.70.94=5N=0.940.94 =1Cl=0.940.94 =1Therefore, the empirical formula is C3H5NCl

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