An unknown amine is treated with an excess of methyl iodide. Two equivalents of methyl iodide react with the amine. The amine is treated with silver oxide and water, and then heated to 120 °C. The resulting products are trimethylamine and ethylene. The unknown amine is
Dear Student,
We can find out the unknown amine by using the concept of Hoffman Elimination.
In the first step, the amine reacts with excess of methyl iodide, a quaternary ammonium iodide is formed.
Reaction with AgO and water gives a quaternary ammonium hydroxide.
Heating this leads to the formation of a less substituted alkene and trimethylamine.
Since ethylene is formed, which contains 2 carbon atoms, the starting amine should be ethylamine.
The unknown amine is Ethylamine.
Hope it helps.
Regards
We can find out the unknown amine by using the concept of Hoffman Elimination.
In the first step, the amine reacts with excess of methyl iodide, a quaternary ammonium iodide is formed.
Reaction with AgO and water gives a quaternary ammonium hydroxide.
Heating this leads to the formation of a less substituted alkene and trimethylamine.
Since ethylene is formed, which contains 2 carbon atoms, the starting amine should be ethylamine.
The unknown amine is Ethylamine.
Hope it helps.
Regards