And 6 ii

Dear Student,
Solution) 6) ii)

Let ABCD be the rhombus in which AC and BD are the diagonals . Let ∠ DAB = 50 ° . We know that diagonals of a rhombus bisect each other at right angle . So, ∠ AOB = ∠ BOC = ∠ COD = ∠ DOA = 90 ° now, we know that adjacent angles of rhombus are supplementary . Now, ∠ ADC + ∠ DAB = 180 ° \Rightarrow ∠ ADC + 50 ° = 180 ° \Rightarrow ∠ ADC = 130 ° We know that diagonals of a rhombus bisect each of the opposite angles . ∠ ADB = \frac{1}{2} ∠ ADC = \frac{1}{2} \times 130 = 65 ° ∠ DAB = \frac{1}{2} ∠ DAB = \frac{1}{2} \times 50 ° = 25 ° In ∆ AOD, ∠ DOA = 90 ° ∠ ADO = 65 ° ∠ DAO = 25 °

Regards!