Anil borrowed a sum of 12300 rs for a certain period at the rate of 10 per cent per annum and returned 18450 rs . Find tbe time for which money was borrowed by him.

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$$\begin{gathered} Given: \\ Anil borrowed sum of money \left(Principal\right)=12300 Rs \\ Rate of Interest \left(R\right)=10\% \\ Total Amount=18450 Rs \\ Find :Time Period \\ Simple Interest \left(SI\right)=Amount-Principal \\ SI=18450-12300 \\ SI=6150 Rs \\ Now U\sin g formula of SI \\ SI=\frac{Principal\times Time Period\times Rate of Interest }{100} \\ 6150=\frac{12300\times Time Period\times 10}{100} \\ Time Period=\frac{6150}{1230} \\ \mathit{T}\mathit{i}\mathit{m}\mathit{e}\mathbf{ }\mathit{P}\mathit{e}\mathit{r}\mathit{i}\mathit{o}\mathit{d}\mathbf{=}\mathbf{5}\mathbf{\hspace{0.17em}}\mathit{y}\mathit{e}\mathit{a}\mathit{r}\mathit{s}\mathbf{ } \\ \mathbf{ }\mathbf{ }\mathit{A}\mathit{n}\mathit{s}\mathit{w}\mathit{e}\mathit{r}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{5}\mathit{y}\mathit{e}\mathit{a}\mathit{r}\mathit{s} \end{gathered}$$


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