Ans :B
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Ans :B Show for all options Column-I (Reaction) (P) NH4N03 N20 + H20 (Q) (NH4)2Cr207 N2 + Cr203 (R) NH4N02 N 2 + H20 (S) Ba + _3N2 Codes : P Q 4 3 2 2 R 3 4 4 s 3 Column-II (Equivalent where M is moleculu mass of reactant) 2 Space for Rough Work

Dear student,

The equivalent weight of the substance = Molecular mass/ change in oxidation number per mole

(P)
NH4NO3-------> 2H2O + N2O

Here, the change in oxidation number per mole is 4.
The equivalent weight of the substance = M/ 4.

​(Q)
(NH4)2Cr2O7-------> Cr2O3 + N2

Here, the change in oxidation number per mole is 6.
The equivalent weight of the substance = M/ 6.

(r)
NH4NO2-------> 2H2O + N2O

Here, the change in oxidation number per mole is 3.
The equivalent weight of the substance = M/ 3.

(s)
Ba(N3)2-------> Ba + 3N2

Here, the change in oxidation number per mole is 2.
The equivalent weight of the substance = M/ 2.

regards