ans b

ans b 9. Res Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 kg-m/s is given to the 5 kg mass. The velocity of the 10 kg mass will be C) 2 m/s D) zero nse Grid:

Given that impulse on 5kg is 60° wrt x-axis; so along x axis its component is given by, I (x)=Icos60° =10×(1/2)=5kgm/s. This impulse given to the system equals the change in linear momentum of centre of mass of the system , so (M+m)v = 5kgm/s (10+5)v = 5kgm/s =》v = 1/3 m/s The 10 kg mass moves with same velocity as that of centre of mass.

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ans b ans b 9. Res Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 kg-m/s is given to the 5 kg mass. The velocity of the 10 kg mass will be C) 2 m/s D) zero nse Grid:

ans b

ans b 9. Res Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 kg-m/s is given to the 5 kg mass. The velocity of the 10 kg mass will be C) 2 m/s D) zero nse Grid: