Ans me pls

Dear student,

Assuming that the unit of heat of formation of CO_{​​​​​2} is - 94 kJ/mol
Then 94 kJ heat is liberated when 1 mole CO_{​​​​​2} is formed.
Or 44 g CO_{​​​​​2} liberates 94 kJ of heat.
Or 1 g CO_{​​​​​2} liberates 94/44 kJ of heat.

Now C + O_{​​​​​​2} ----> CO_{​​​​​2}
Hence 12 g graphite (C) releases 44 g carbon dioxide.
3 g C releases = 44/4 = 11 g CO_{​​​​​2} 

Heat liberated from 11 g CO_{​​​​​2} = (94/44)*11 = 23.5 kJ
Therefore, option '1' is correct.


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