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22. AB is the diameter of a given circle with centre O. If PA=PB and  PAC=20o, find the value of 
PAB and  ABC. 

Dear student

Given: PA=PBPAB=PBA=x sayAlso, APB=90°  angle in a semicircleConsider PAB, by angle sum propertyPAB+ABP+APB=180°x+x+90°=180°2x=90°x=45°So, PAB=45°Also, ACB=90°  angle in a semicircleand CAB=PAB-PAC=45°-20°=25°Consider CAB, by angle sum propertyCAB+ABC+BCA=180°25°+ABP+PBC+90°=180°25°+45°+PBC+90°=180°PBC=20°So, ABC=ABP+PBC=45°+20°=65°
Regards

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