x2 - 2 - 3x - 23 = 0⇒x2 - 2 - 3x +-2 -322 - 23 - -2 -322= 0⇒x2 - 2 - 3x +2 -322 = 23 + 2 -322⇒x2 - 2 × x × 2 -32+2 -322 = 23 + 4 + 3 - 434⇒x -2 -32 2 = 4 + 3 + 434⇒x -2 -32 2 = 2 + 322⇒x -2 -32 = ± 2 + 32⇒x = 2 -32 + 2 + 32 or x = 2 -32 - 2 + 32⇒x = 2 - 3 + 2 + 32 or x = 2 -3 -2 - 32⇒x = 2 or x = -3

Ans plz

x^{2} - (2 - \sqrt{3}) x - 2 \sqrt{3} = 0 \Rightarrow x^{2} - (2 - \sqrt{3}) x + {[- \frac{(2 - \sqrt{3})}{2}]}^{2} - 2 \sqrt{3} - {[- \frac{(2 - \sqrt{3})}{2}]}^{2} = 0 \Rightarrow x^{2} - (2 - \sqrt{3}) x + {[\frac{(2 - \sqrt{3})}{2}]}^{2} = 2 \sqrt{3} + {[\frac{(2 - \sqrt{3})}{2}]}^{2} \Rightarrow x^{2} - 2 \times (x) \times \frac{(2 - \sqrt{3})}{2} + {[\frac{(2 - \sqrt{3})}{2}]}^{2} = 2 \sqrt{3} + \frac{4 + 3 - 4 \sqrt{3}}{4} \Rightarrow {[x - (\frac{2 - \sqrt{3}}{2})]}^{2} = \frac{4 + 3 + 4 \sqrt{3}}{4} \Rightarrow {[x - (\frac{2 - \sqrt{3}}{2})]}^{2} = {(\frac{2 + \sqrt{3}}{2})}^{2} \Rightarrow [x - (\frac{2 - \sqrt{3}}{2})] = \pm (\frac{2 + \sqrt{3}}{2}) \Rightarrow x = \frac{2 - \sqrt{3}}{2} + \frac{2 + \sqrt{3}}{2} or x = \frac{2 - \sqrt{3}}{2} - \frac{2 + \sqrt{3}}{2} \Rightarrow x = \frac{2 - \sqrt{3} + 2 + \sqrt{3}}{2} or x = \frac{2 - \sqrt{3} - 2 - \sqrt{3}}{2} \Rightarrow x = 2 or x = - \sqrt{3}

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